60=15x^2+x+10

Solution for 60=15x^2+x+10 equation:

60=15x^2+x+10

We move all terms to the left:

60-(15x^2+x+10)=0

We get rid of parentheses

-15x^2-x-10+60=0

We add all the numbers together, and all the variables

-15x^2-1x+50=0

a = -15; b = -1; c = +50;
Δ = b2-4ac
Δ = -12-4·(-15)·50
Δ = 3001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3001}}{2*-15}=\frac{1-\sqrt{3001}}{-30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3001}}{2*-15}=\frac{1+\sqrt{3001}}{-30}
$